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-x^2-22+5x=-9x^2-2+5x
We move all terms to the left:
-x^2-22+5x-(-9x^2-2+5x)=0
We add all the numbers together, and all the variables
-1x^2-(-9x^2-2+5x)+5x-22=0
We get rid of parentheses
-1x^2+9x^2-5x+5x+2-22=0
We add all the numbers together, and all the variables
8x^2-20=0
a = 8; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·8·(-20)
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{10}}{2*8}=\frac{0-8\sqrt{10}}{16} =-\frac{8\sqrt{10}}{16} =-\frac{\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{10}}{2*8}=\frac{0+8\sqrt{10}}{16} =\frac{8\sqrt{10}}{16} =\frac{\sqrt{10}}{2} $
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